(I) determine the tangential and centripetal components of the net force excreted on the car(by the ground) when it accelerates at a uniform speed of 15 m/s in 11 s, moving on a circular track of radius 500m. The cars mass is 1100kg.
accelerates at a uniform speed of 15 m/s in 11 s
Please rephrase this, it makes no sense
I'm sorry when it's speed is 15 m/s. doesn't say uniform
To determine the tangential and centripetal components of the net force exerted on the car by the ground, we need to use the following equations:
1. Tangential Force (Ft) = Mass (m) * Tangential Acceleration (at)
2. Centripetal Force (Fc) = Mass (m) * Centripetal Acceleration (ac)
First, let's find the tangential acceleration. The car is moving at a uniform speed of 15 m/s, which means its velocity doesn't change. Therefore, there is no tangential acceleration. Hence, the tangential force is zero.
Next, let's determine the centripetal acceleration. The formula for centripetal acceleration is:
Centripetal Acceleration (ac) = (Velocity (v))^2 / Radius (r)
Plugging in the values:
ac = (15 m/s)^2 / 500 m
ac = 225 m^2/s^2 / 500 m
ac = 0.45 m/s^2
Now we can calculate the centripetal force using the centripetal acceleration and the car's mass:
Fc = Mass (m) * Centripetal Acceleration (ac)
Fc = 1100 kg * 0.45 m/s^2
Fc = 495 N
Therefore, the tangential force is zero, and the centripetal force exerted on the car by the ground is 495 Newtons.