Posted by **Eric** on Saturday, May 18, 2013 at 11:54am.

Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x

function= t^2-4/(1+cos(t)^2) dt

x^2-4/(1+cos(x)^2)= 0

x^2-4=0

x^2=4

x= +/- 2

So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me more maxima like +/-4.99, +/-7.999, etc. How did they get those values? Can someone please explain that to me? Thank you for your time.

Sorry I wrote the wrong variable in the last posting (this is a correction).

I got +/-4.99 and +/-7.99 when I typed the keyword 'local maximum x^2-4/(1+cos(x)^2)'

into the equation box. It just gave me a list of maxima.

## Answer This Question

## Related Questions

- Calculus - Find and classify the relative maxima and minima of f(x) if f(x)= ...
- Extrema-Check my work please? - Find and classify the relative maxima and minima...
- Followup-Calculus-Extrema - Find and classify the relative maxima and minima of ...
- calculus - If g is a differentiable function such that g(x) is less than 0 for ...
- differentiability - If g is a differentiable function such that g(x) is less ...
- Calculus - Find the values of x that give relative extrema for the function f(x...
- calculus-extrema - Find and classify the relative maxima and minima of this ...
- Extrema-Calc - Find and classify the relative maxima and minima of this function...
- calculus - Consider the function f(x) = e^sin(cos(x)) on the interval [0, 4?] a...
- Calculus - Let f(x) = 2x^{3}+9. Find the open intervals on which f is increasing...

More Related Questions