Wednesday

July 23, 2014

July 23, 2014

Posted by **Eric** on Saturday, May 18, 2013 at 11:54am.

function= t^2-4/(1+cos(t)^2) dt

x^2-4/(1+cos(x)^2)= 0

x^2-4=0

x^2=4

x= +/- 2

So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me more maxima like +/-4.99, +/-7.999, etc. How did they get those values? Can someone please explain that to me? Thank you for your time.

Sorry I wrote the wrong variable in the last posting (this is a correction).

I got +/-4.99 and +/-7.99 when I typed the keyword 'local maximum x^2-4/(1+cos(x)^2)'

into the equation box. It just gave me a list of maxima.

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