Friday

November 28, 2014

November 28, 2014

Posted by **Kate** on Saturday, May 18, 2013 at 9:37am.

a) arctan(-sqrt(3))

a) Arctan(-sqrt(3))

So, I know how to find the answers with a calculator, but how do I find it step by step?

- TRIGONOMETRY -
**Steve**, Saturday, May 18, 2013 at 11:47amby test time you need to know the "standard" angles with easy-to-recall trig functions

0,π/6,π/4,π/3,π/2

If you know those angles and their trig ratios, you will recall that

tan π/3 = √3

Now, recall the bit about principal values of inverse trig functions. You restrict the domain so that the range is one continuous period, containing 0, if possible.

-π/2 <= Arcsin(x) < π/2

0 <= Arccos(x) <= π

-π/2 < Arctan(x) < π/2

...

arctan(-√3) = -π/3 + 2kπ

Arctan(-√3) = -π/3

- TRIGONOMETRY -
**Kate**, Saturday, May 18, 2013 at 1:28pmAah, okay! That's easy enough! That makes total sense. Thanks!

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