Posted by Lily on Saturday, May 18, 2013 at 9:19am.
Solve the system: y^2 - 4x^2 = 4 and y = 2x.
Algebra 2 - Steve, Saturday, May 18, 2013 at 11:58am
did you plug in your values to see whether they work?
Guess not, since (-1,-2) yields
(-2)^2 - 4(-1) = 4
4 + 4 = 4
Since y=2x, substitute it into the other equation:
(2x)^2 - 4x^2 = 4
4x^2 - 4x^2 = 4
0 = 4
Bzzzt. No solutions
Algebra 2 - Lily, Saturday, May 18, 2013 at 12:04pm
It feels like too many problems have no solutions! Very frustrating for me. Thank you for checking it!
Algebra 2 - Steve, Saturday, May 18, 2013 at 12:11pm
Yeah, they have tossed a lot of them your way. Expect some on the test, I guess. Always check you proposed answer, if you get one, to make sure it works!
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