Posted by Lily on .
Find the exact solutions of x^2  (y  12)^2 = 144 and y = x^2.
No solution?

Algebra 2 
Steve,
second verse, same as the first:
y = x^2, so
x^2  (x^2  12)^2 = 144
x^2  x^4  24x^2  144 = 144
x^4 + 23x^2 + 288 = 0
again, the discriminant is negative, so there are no solutions.
x=0 works only in the 2nd equation
(±12,12) only works in the first equation 
Algebra 2 
Lily,
Thank you!