f(x) = x*3 - 6x*2 + 9x - 1
find max meaning of function on [0; 2] segment
f(x) = x^3 - 6x^2 + 9x - 1
f'(x) = 3x^2 - 12x + 9
= 3(x-1)(x-3)
f(1) = 3 a max
f(3) = -1 a min
On the interval [0,2]
f(1) will be the max
find max meaning of function on [0; 2] segment
f'(x) = 3x^2 - 12x + 9
= 3(x-1)(x-3)
f(1) = 3 a max
f(3) = -1 a min
On the interval [0,2]
f(1) will be the max