Posted by Lily on Friday, May 17, 2013 at 10:06am.
Find the exact solutions of x^2  (y  6)^2 = 36 and y = x^2.
(0,0), (6,6), and (6,6)?

Algebra 2  Steve, Friday, May 17, 2013 at 10:30am
Hmmm.
y = x^2 so
x^2  (x^26)^2 = 36
x^2  x^4  12x^2  36 = 36
x^4 + 11x^2 + 72 = 0
I don't see any real solutions. 11^24*72 < 0

Algebra 2  Lily, Friday, May 17, 2013 at 10:42am
Thanks

Algebra 2  Steve, Friday, May 17, 2013 at 10:49am
And yet, I do see that your points work.
Hmmm.

Algebra 2  Steve, Friday, May 17, 2013 at 10:53am
No, they don't they fit the first equation, but not the 2nd.
Only (0,0) works in both

Algebra 2  Steve, Friday, May 17, 2013 at 10:55am
Nope. (0,0) does not work in the 1st.
0  36 ≠ 36
Can't believe I let you fool me! :)

Algebra 2  Lily, Friday, May 17, 2013 at 11:24am
At this point, I'm fooling myself!:)
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