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March 30, 2017

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how many turn around points are in the function f(x)=(x-1/3)^2(x-2)^3

  • algebra - ,

    f(x) has two roots
    it touches the x-axis at x = 1/3, so that's one turning point.
    It turns again so it can cross the x-axis at x=2

    so, 2 turning points

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