Freshman Sophomore Junior Senior

Left-handed batters 4 6 5 4
Right-handed batters 13 10 11 12

A school baseball team has 65 players. What is the probability that a randomly chosen player is a junior or a right-handed batter?

51/65 P(A OR B)+P(B)-P(A and B)

16/65+46/65-11/65=51/65
The required probability is 51/65

Degree of the polynomial (z2-4)(z3-2)(z4+3)______

(z2-4)(z3-2)(z4+3)

16/65

To find the probability that a randomly chosen player is a junior or a right-handed batter, we need to determine the number of players that meet either of these criteria and divide it by the total number of players on the team.

From the given table, we can see that the number of junior players is 5 and the number of right-handed batters is 11. However, we need to be careful not to double count any players that satisfy both conditions.

To calculate the number of players who are both juniors and right-handed batters, we need to find the intersection between the junior players and the right-handed batters. Looking at the table, we can see that there are 2 students who fall into both categories (junior and right-handed batter).

To find the total number of players who are either juniors or right-handed batters, we need to add the number of junior players (5) and the number of right-handed batters (11), and then subtract the number of players who meet both criteria (2).

Total = Junior players + Right-handed batters - Players who meet both criteria
Total = 5 + 11 - 2
Total = 14

Now we can calculate the probability by dividing the total number of players who meet the criteria (14) by the total number of players on the team (65).

Probability = Number of players meeting the criteria / Total number of players on the team
Probability = 14 / 65
Probability ≈ 0.215 (rounded to three decimal places)

Therefore, the probability that a randomly chosen player is a junior or a right-handed batter is approximately 0.215.