What percent of runners completed the time trial between 52.0and 53.9 seconds?
What is mean and standard deviation?
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z scores. Multiply by 100.
To determine the percentage of runners who completed the time trial between 52.0 and 53.9 seconds, you need two pieces of information: the number of runners who completed the trial within that time range and the total number of runners. Without these specific numbers, it is not possible to provide an accurate percentage. Please provide these details for a precise answer.
To determine the percentage of runners who completed the time trial between 52.0 and 53.9 seconds, you would need to know the total number of runners and the number of runners who finished within that time range. With that information, you can follow these steps:
1. Calculate the number of runners who completed the time trial between 52.0 and 53.9 seconds.
2. Divide the number of runners in step 1 by the total number of runners.
3. Multiply the result by 100 to convert it into a percentage.
Unfortunately, you didn't provide the necessary data to determine the answer accurately. If you have the total number of runners and the number of runners who finished within the specified time range, I would be happy to help you calculate the percentage.