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A runner dashes from the starting line (x=0) to a point 108 m away and then turns around and runs to a point 19 m away from the starting point in 23.4 seconds. To the nearest tenth of a m/s what is the average speed?

  • physics -

    total distance: 108 + 89 = 197m

    so, avg speed is 197m/23.4s = 8.4m/s

    assuming he stopped 19m short of the starting line, and not 19m past it!

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