A runner dashes from the starting line (x=0) to a point 108 m away and then turns around and runs to a point 19 m away from the starting point in 23.4 seconds. To the nearest tenth of a m/s what is the average speed?
physics - Steve, Wednesday, May 15, 2013 at 4:05pm
total distance: 108 + 89 = 197m
so, avg speed is 197m/23.4s = 8.4m/s
assuming he stopped 19m short of the starting line, and not 19m past it!