Tuesday

July 22, 2014

July 22, 2014

Posted by **Eric** on Wednesday, May 15, 2013 at 1:50pm.

upper sum: 3sqrt(3) + 3sqrt(6)

lower sum: 3sqrt(3) + 3

but this is incorrect. can someone explain what i did wrong please

- Sums-Calc -
**Steve**, Wednesday, May 15, 2013 at 3:02pmThe width of interval [1,3] is 2, not 3

- Sums-Calc -
**Eric**, Wednesday, May 15, 2013 at 4:50pmI see what I did now. Thanks

**Related Questions**

Upper-lower bounds-solved - find the upper and lower bounds for definite ...

Calculus - Solve these indefinite and definite integrals. [integration sign] 4j-...

Calc - (1/1+(4/n))(4/n)+(1/1+(8/n))(4/n)+(1/1+(12/n))(4/n)+....+(1/1+(4n/n))(4/n...

Calculus - We're doing a lab in my Calc II class and I'm stuck on this question...

abstract algebra - Suppose K = {{2,3,4,5,6,7},{2,5,7,8,12},{1,2,3,5,7,9,13,20...

abstract algebra - Suppose K = {{2,3,4,5,6,7},{2,5,7,8,12},{1,2,3,5,7,9,13,20...

calculus - Evaluate the definite integral: upper number of the integral is 6 ...

Calculus Fundamental Theorem - Evaluate the definite integral. function: (t+8)(t...

Maths - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2...

Math - The following sum [(sqrt(36-((6/n)^2))).(6/n)] + [(sqrt(36-((12/n)^2))).(...