Sunday

August 31, 2014

August 31, 2014

Posted by **Leah** on Wednesday, May 15, 2013 at 12:17pm.

My answer turns out to be incorrect despite my checking it several times. I got -2/3t* sqrt(t^2+1)

Can someone explain to me what is wrong with my answer and how to go about obtaining it the right way? Thank you everyone. :-)

- D/dt -
**Steve**, Wednesday, May 15, 2013 at 2:54pmf(t) = ∫[2,t^2] √(x+1) dx

df/dt = √(t^2+1) (2t)

Recall that d/dt ∫[a,b(t)] f(x) dx = f(b(t)) db/dt

see wikipedia's article on differentiating under the integral sign.

- D/dt -
**Leah**, Wednesday, May 15, 2013 at 5:02pmThank you for the equation and the useful article. :)

So this is what I get.

f(t) dt= 2(0)- [sqrt(t^2+1) * 2t]

f(t) dt= -sqrt(t^2+1) *2t

Is this correct? Thank you so much. :-)

**Related Questions**

Calculus (Checking Answer) - Find the antiderivative by hand in each case. S ...

Calc. Checking Answer - Find the antiderivative by hand in each case. S stands ...

Math Help please!! - Could someone show me how to solve these problems step by ...

Calculus - Please look at my work below: Solve the initial-value problem. y'' + ...

Algebra - How do you simplify this? -16^(1/4) Someone showed me like this: (-1)(...

MATH - I need to simply this equation, but I got stuck. h/(4-sqrt(16+h)) = y ...

math,algebra,help - Directions are simplify by combining like terms. x radiacal ...

Math - How do you find a square root of a number that's not a perfect square? I'...

Inequality - When I solve the inquality 2x^2 - 6 < 0, I get x < + or - ...

Math/Calculus - Solve the initial-value problem. Am I using the wrong value for ...