Thursday

July 24, 2014

July 24, 2014

Posted by **Leah** on Wednesday, May 15, 2013 at 12:17pm.

My answer turns out to be incorrect despite my checking it several times. I got -2/3t* sqrt(t^2+1)

Can someone explain to me what is wrong with my answer and how to go about obtaining it the right way? Thank you everyone. :-)

- D/dt -
**Steve**, Wednesday, May 15, 2013 at 2:54pmf(t) = ∫[2,t^2] √(x+1) dx

df/dt = √(t^2+1) (2t)

Recall that d/dt ∫[a,b(t)] f(x) dx = f(b(t)) db/dt

see wikipedia's article on differentiating under the integral sign.

- D/dt -
**Leah**, Wednesday, May 15, 2013 at 5:02pmThank you for the equation and the useful article. :)

So this is what I get.

f(t) dt= 2(0)- [sqrt(t^2+1) * 2t]

f(t) dt= -sqrt(t^2+1) *2t

Is this correct? Thank you so much. :-)

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