-10i(5+8i)

oh yeah it says to simplify but I have no clue at all as to how to do this it is a complex number problem I think does anyone know how to do this?(im the one that posted the question)

remember , for complex numbers

i =√-1 , and i^2 = -1

-10i(5+8i)
= -50i - 80i^2 , treating i just like any ol' variable.
= -50i - 80(-1)
= 80 - 50i

To simplify the expression -10i(5+8i), we need to multiply -10i by each term inside the parentheses.

Let's start with the first term, -10i, and multiply it by 5:
-10i * 5 = -50i

Now, let's move on to the second term, -10i, and multiply it by 8i:
-10i * 8i = -80i^2

Remember that i^2 is equal to -1, so we can substitute -80i^2 with -80(-1):
-80i^2 = -80(-1) = 80

Therefore, the simplified expression is -50i + 80.

To simplify the expression -10i(5+8i), you can distribute the -10i to both terms inside the parentheses.

Let's break it down step by step:

First, multiply -10i with 5:

-10i * 5 = -50i

Next, multiply -10i with 8i:

-10i * 8i = -80i^2

Remember that i^2 is equal to -1, so we substitute -1 for i^2:

-80i^2 = -80(-1) = 80

Putting the two results together, we have:

-10i(5+8i) = -50i + 80