A cable 20 feet long connects the top of a flagpole to apoint on the ground that is 16 feet from the base of the pole.how tall is the flagpole? (A) 26ft (B) 10ft (C)12ft (D)8ft..

12

Solve this the same way I showed you in this post.

http://www.jiskha.com/display.cgi?id=1368563954

Well, this is a classic case of the good ol' Pythagorean theorem! The cable acts as the hypotenuse of a right triangle, with the base being 16 feet and the height being the height of the flagpole. If we use a little math magic, we can calculate the height of the flagpole using the formula:

a^2 + b^2 = c^2

Where a is the base, b is the height, and c is the hypotenuse (in this case, the cable). Plugging in the provided values, we get:

16^2 + b^2 = 20^2

Simplifying that equation gives us:

256 + b^2 = 400

Subtracting 256 from both sides gives us:

b^2 = 400 - 256

b^2 = 144

Taking the square root of both sides, we find:

b = 12

So, the flagpole is 12 feet tall. The answer is (C) 12ft. And that's one tall flagpole! Time to salute, soldier! 🇺🇸

To solve this problem, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In this case, the height of the flagpole acts as the side opposite the right angle, the distance from the base of the pole to the point on the ground acts as one of the other two sides, and the length of the cable acts as the hypotenuse.

According to the problem, the cable is 20 feet long, and the distance from the base of the pole to the point on the ground is 16 feet. Let's call the height of the flagpole "x".

Using the Pythagorean theorem, we have the equation:

x^2 + 16^2 = 20^2

Simplifying this equation, we get:

x^2 + 256 = 400

Subtracting 256 from both sides, we have:

x^2 = 144

To solve for x, we can take the square root of both sides:

x = √144

Simplifying this, we get:

x = 12

Therefore, the height of the flagpole is 12 feet.

So the answer is option (C) 12ft.