Posted by **jamesbond** on Tuesday, May 14, 2013 at 2:16pm.

What are the last 2 digits of 43^2082?

- math helllllllllllpppp plzzzzzzzzzzzzzzzzzzzzzzz -
**Reiny**, Tuesday, May 14, 2013 at 3:35pm
43^0 = 1 or 01

43^1 = 43

43^2 = 1849

43^3 = 79507

43^4 = 3418801

43^5 = 147008443

43^6 = ......049

43^7 = ..... 07

43^8 = ..... 01

43^9 = ..... 43

ahhh, can you see how the end repeats ?

ending: 43 49 07 01 43 repeats after 4 numbers

2082/4 = 520 and remainder of 1

and behaves like

43^1 , 1/4 = 0 and a remainder of 1 ---ends in 43

43^9, 9/4 = 2 and a remainder of 1 --- ends in 43

..

43^2082 , 2082/4 = 520 and a remainder of 1 --- ends in 43

So 43^2082 ends in a 43

## Answer This Question

## Related Questions

- math - x has 3 digits. the tens digits is half the hundreds digits. the number ...
- math - My hundred digits are less than 10 digits and ones digits are greater ...
- math master need your help - what is next number in the sequence 12,6,4,3,2,12/5...
- math - Solve the mathematical puzzle. Determine the digits of F from these clues...
- 7th grade math "Math Makes Me Think" - Day 15: What's my number? It has 3 digits...
- Math - If no digits may be used more than once , how many 5 digits can be formed...
- Math - What am I? I am a decimal fraction with three digits I am bigger than ...
- math - A locker combination has three nonzero digits, and digits cannot be ...
- Math - A locker combination has three nonzero digits, and digits cannot be ...
- Math - A locker combination has three nonzero digits, and digits cannot be ...

More Related Questions