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posted by Vicki on Tuesday, May 14, 2013 at 11:35am.
How many grams of barium nitrate is needed to form a solution with 5.00 mass% Ba (NO3)2 in 400 grams of water.
% by mass = (mass solute/g soln)*100 let x = mass solute [(x)/(400+x)]*100 = 5 Solve for x.
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