What is the magnitude of the electrostatic force on a +5 C harge 1.75 m to the left of a -2.5 C Charge? (show your work)

k =9•10⁹ N•m²/C²

F=k•q₁•q₂/r² =
=9•10⁹•5•2.5/1.75² =3.67•10¹⁰ N (to the right)

To calculate the magnitude of the electrostatic force between two charges, we can use Coulomb's Law. The formula for the electrostatic force between two charges q1 and q2 separated by a distance r is:

F = k * (|q1| * |q2|) / r^2

Where F is the magnitude of the electrostatic force, k is Coulomb's constant (k = 8.99 x 10^9 N·m^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

Given:
q1 = +5 C (Charge 1)
q2 = -2.5 C (Charge 2)
r = 1.75 m

First, let's calculate the magnitude of the electrostatic force using Coulomb's Law:

F = (8.99 x 10^9 N·m^2/C^2) * ((+5 C) * (-2.5 C)) / (1.75 m)^2

Now, we can simplify and solve the equation:

F = (8.99 x 10^9 N·m^2/C^2) * (-12.5 C^2) / (3.0625 m^2)
F = -109.387755 C^2 * N / m^2

So, the magnitude of the electrostatic force on the +5 C charge 1.75 m to the left of the -2.5 C charge is approximately 109.39 N.