SD TRUSS PROBLEM WITH THE METHOD OF JOINTS
The truss structure ABCD is loaded with a concentrated force P = 2 kN applied at a 45° angle at joint D as indicated in the figure. All bars in the truss have equal cross sectional area and are made of the same homogeneous linear elastic material. The dimensions are H=3 m and L=8 m. Use the method of joints to obtain the axial forces in the bars and the Cartesian components of the reactions at the supports A and C.
1_A, 1_B, 1_C
1_A : -1.17, -1.17, 1.4142, 0.936, 2.35
1_B : -1.414, 0.702, 0.702
1_C:-4.05, -4.05,2.59,6.49
Anyone for HW4_2: Part I?
4_2 part IIA RxA=4, RyA=0
4_2 part IIB RxE=4, RyE=2
RxA= -4, sorry
problem 4_2 part :1
A load W=2 kN is applied vertically to joint C of truss ABCDE as indicated.
plz help
Please HW4_2: Part I?
Anybody for Problem: HW4_2: Part I please?
Has somebody formula for HW4_2: Part I?
N_AB N_BC N_BE N_BD N_CD N_ED
-1 1 -0,7071 0 0 0
0 0 -0,7071 -1 0 0
0 -1 0 0 -0,7071 0
0 0 0 0 -0,7071 0
0 0 0 0 0,7071 -1
0 0 0 1 0,7071 0
b
0
0
0
2
0
0
X = a\b
N AB 4,000
N BC 2,000
N BE -2,828
N BD 2,000
N CD -2,828
N ED -2,000
Simonsay thanks. Something is wrong with the expression, could you please check?
I don't get right answer.