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SD TRUSS PROBLEM WITH THE METHOD OF JOINTS

The truss structure ABCD is loaded with a concentrated force P = 2 kN applied at a 45° angle at joint D as indicated in the figure. All bars in the truss have equal cross sectional area and are made of the same homogeneous linear elastic material. The dimensions are H=3 m and L=8 m. Use the method of joints to obtain the axial forces in the bars and the Cartesian components of the reactions at the supports A and C.

1_A, 1_B, 1_C

  • Physics - ,

    1_A : -1.17, -1.17, 1.4142, 0.936, 2.35
    1_B : -1.414, 0.702, 0.702

  • Physics - ,

    1_C:-4.05, -4.05,2.59,6.49

    Anyone for HW4_2: Part I?

  • Physics - ,

    4_2 part IIA RxA=4, RyA=0
    4_2 part IIB RxE=4, RyE=2

  • Physics - ,

    RxA= -4, sorry

  • Physics - ,

    problem 4_2 part :1
    A load W=2 kN is applied vertically to joint C of truss ABCDE as indicated.
    plz help

  • Physics - ,

    Please HW4_2: Part I?

  • Physics - ,

    Anybody for Problem: HW4_2: Part I please?

  • Physics - ,

    Has somebody formula for HW4_2: Part I?

  • Physics - ,

    N_AB N_BC N_BE N_BD N_CD N_ED
    -1 1 -0,7071 0 0 0
    0 0 -0,7071 -1 0 0
    0 -1 0 0 -0,7071 0
    0 0 0 0 -0,7071 0
    0 0 0 0 0,7071 -1
    0 0 0 1 0,7071 0

    b

    0
    0
    0
    2
    0
    0

    X = a\b

    N AB 4,000
    N BC 2,000
    N BE -2,828
    N BD 2,000
    N CD -2,828
    N ED -2,000

  • Physics - ,

    Simonsay thanks. Something is wrong with the expression, could you please check?
    I don't get right answer.

  • Physics - ,

    -1,1,-0.7071,0,0,0
    0,0,-0.7071,-1,0,0
    0,-1,0,0,-0.7071,0
    0,0,0,0,-0.7071,0
    0,0,0,0,0.7071,-1
    0,0,0,1,0.7071,0

    1/sqrt(2) = 1/1.4142 = 0.7071

  • Physics - ,

    Simonsay, is that like this below? I have just tried it does not give right answer and says:
    Expression or statement is incomplete or incorrect.

    ANy help please and did someone manage?

    % Define the coefficient matrix a
    a =
    N_AB -1,1,-0.7071,0,0,0
    N_BC 0,0,-0.7071,1,0,0
    N_BE 0,-1,0,0,-0.7071,0
    N_BD 0,0,0,0,-0.7071,0
    N_CD 0,0,0,0,0.7071,-1
    N_ED 0,0,0,1,0.7071,0

    % Define the right-hand-side vector b
    b =
    0
    0
    0
    2
    0
    0

    % Solve for solution vector
    X = a\b
    N_AB 4,000
    N_BC 2,000
    N_BE -2,828
    N_BD 2,000
    N_CD -2,828
    N_ED -2,000

  • Physics - ,

    Please help simonsay! Have problem with expresion too.

  • Physics - ,

    try C/P this

    % Define the coefficient matrix a
    a =[-1 1 -sqrt(2)/2 0 0 0; 0 0 -sqrt(2)/2 -1 0 0; 0 -1 0 0 -sqrt(2)/2 0; 0 0 0 0 -sqrt(2)/2 0;
    0 0 0 0 sqrt(2)/2 -1; 0 0 0 1 sqrt(2)/2 0];

    % Define the right-hand-side vector b
    b = [0; 0 ; 0; 2; 0; 0];

    % Solve for solution vector
    X = a\b

  • Physics - ,

    you must type the numbers, curly N just to indicate where is aplied

  • Physics - ,

    Thanks regz and simonsay!

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