Wednesday

August 27, 2014

August 27, 2014

Posted by **Chloe** on Tuesday, May 14, 2013 at 2:24am.

Data:

Nernst Equation: Ecell=E0cell -RT/nF ln Q

Questions:

1. I am not sure if i did the E0cell right equation, I switched the Ecell to get the E0cell..and "n" is equal to 2 moles being transfer?

I calculated:

Measured Ecell = 0.445V

Overall rxn = Cu(s)+Pb2(aq) ~ CU2+(aq) + Pb(s)

N= 2moles??

Re-arrange the equation:

E0cell = Ecell - RT/nF ln Q

E0cell = 0.445V -(8.314 j/k*mol *298K)/(2 moles * 96500 c/mole e-) ln (0.10)

= -2.30

2. Overall reaction:

3Pb(s) + 2Al 3+ (aq) ~ 3Pb2+(aq) = 2Al(s)

Measured Ecell(V) = 0.086V

N= 6moles?? (3*2 moles)

0.086V- (8.314 j/k*mol * 298K)/ (6moles * 96500 C/mole e- ) ln (0.10/0.10^6) = 0.94??

Is this right? Please help! Thank you in advance!

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