Posted by **Yasemine** on Monday, May 13, 2013 at 10:33pm.

We have an important chemsitry test due and I want to make sure that I do not mess up on my algebra. I am dealing with the integrated rate law, but my question is purely algebraically in nature. I hope, somebody can help me.

1) ln(A) = -kt+ln(B)

solve for t

solve for k

solve for B

2) 1/(B) = kt + 1/(B)

solve for k

solve for t

solve for B

Thank you so much for your help. It is greatly appreciated

- Math -
**Reiny**, Monday, May 13, 2013 at 10:45pm
1)

ln(A) = -kt+ln(B)

kt = lnB - lnA

kt = ln(B/A)

t = ln(B/A) / k

k = ln(B/A) / t

lnB = lnA + kt

B = e^(lnA + kt)

2)

1/B = kt + 1/B

0 = kt

t = 0

or

k = 0

B is any value except B≠0

(are you sure you have no typo in 2) ?

- Math -
**Yasemine**, Monday, May 13, 2013 at 10:50pm
2) should be 1/(B) = kt+1(A)

I am dealing with concentrations and A and B are just placeholders for the concentrations.

Thanks

- Math -
**Reiny**, Monday, May 13, 2013 at 11:00pm
2) I thought there was something wrong with your first typing of the question

1/B = kt + 1/A

multiply each term by AB, the LCD

A = ABkt + B

A - B = ABkt

t = (A-B)/(ABk)

k = (A-b)/(ABt)

from: A = ABkt + B

A = B(Akt + 1)

B = A/(Akt + 1)

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