Wednesday

August 20, 2014

August 20, 2014

Posted by **Liz** on Monday, May 13, 2013 at 5:24pm.

3x^2+36x+3y^2=0

- Find the center (h,k) and radius -
**Steve**, Monday, May 13, 2013 at 6:03pm3x^2+36x+3y^2=0

x^2+12x+y^2=0

(x^2+12x+36) + y^2 = 36

(x+6)^2 + y^2 = 36

hat should make it easy to get the required info.

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