Given that alpha=30 degrees, a=6, and b=12. What is the number of triangles possible under these conditions?
I trust you are using standard convention , so that side a is opposite angle A
let's find angle B
sinB/12 = sin30°/6
sinB = 12sin30/6 = 1
so angle B = 90°
so one triangle is possible and it is a right-angled triangle