6(y²-2) + y < 0
6y^2 + y - 12 < 0
(3y-4)(2y+3) < 0
the intercepts of the corresponding parabola would be 4/3 and -3/2
and we want the part of the parabola which is negative
so -3/2 < y < 4/3
(3y-4)(2y+3) < 0
the intercepts of the corresponding parabola would be 4/3 and -3/2
and we want the part of the parabola which is negative
so -3/2 < y < 4/3