2.76 grams of silver carbonate produced a 50 percent yield of silver oxide. what is the actual mass of this reaction
g Ag2O = g Ag2CO3 x (molar mass Ag2O/molar masss Ag2CO3) = ? at 100% yield.
That times 0.50 = g Ag2O actually produced.
That times 0.50 = g Ag2O actually produced.