Determine the quantity of stock 75.0% v/v EtOH required to prepare 300ml of a 25.0% v/v EtOH solution
quantity here refers to the volume you need to extract from the 75% ethanol to make 25% ethanol in 300ml.
i would use a dilution equation c1v1=c2v2 and find v2 such that;
v1=(c2/v2)/c1 where c1 is 75%, c2 is 25%, v2 is 300ml.
hope that helps
Oh, you're asking me to do some math? Well, I'm more of a joker than a mathematician, but I'll give it a shot!
To figure out how much 75.0% v/v EtOH stock solution you'll need, we can use a little algebra. Let's call the quantity of stock solution we need "x." We know that the final volume should be 300 ml, and the final concentration is 25.0% v/v.
So, we can set up the equation:
0.75x + 0 (because we won't be diluting the stock solution) = 0.25 * 300
Simplifying it a bit:
0.75x = 0.25 * 300
Now, let's do some multiplication and division dance moves:
0.75x = 75
And now, the grand finale:
x = 75 / 0.75
Drum roll, please...
x = 100
So, you would need 100 ml of the 75.0% v/v EtOH stock solution to prepare 300 ml of a 25.0% v/v EtOH solution. Ta-da!
To determine the quantity of stock 75.0% v/v EtOH required to prepare 300ml of a 25.0% v/v EtOH solution, you can use the following formula:
(C1)(V1) = (C2)(V2)
Where:
C1 = concentration of the stock solution (in this case, 75.0%)
V1 = volume of the stock solution needed
C2 = concentration of the desired solution (in this case, 25.0%)
V2 = volume of the desired solution (in this case, 300ml)
Let's calculate the volume of the stock solution needed:
(75.0%)(V1) = (25.0%)(300ml)
Cross-multiplying:
(75.0/100)(V1) = (25.0/100)(300)
Simplifying:
0.75(V1) = 0.25(300)
Dividing both sides by 0.75:
V1 = (0.25)(300) / 0.75
Calculating:
V1 = 100 ml
Therefore, you will need 100 ml of the stock 75.0% v/v EtOH solution to prepare 300 ml of a 25.0% v/v EtOH solution.
To determine the quantity of a stock solution required to prepare a certain concentration of a solution, you need to use a formula called the "Dilution Formula."
The dilution formula is represented as:
C₁V₁ = C₂V₂
Where:
C₁ = Concentration of the initial (stock) solution
V₁ = Volume of the initial (stock) solution
C₂ = Concentration of the desired solution
V₂ = Volume of the desired solution
In this case, you want to prepare a 25.0% v/v EtOH solution using a 75.0% v/v EtOH stock solution. Let's apply the formula:
C₁ = 75.0% v/v = 75.0/100
V₁ = ?
C₂ = 25.0% v/v = 25.0/100
V₂ = 300 mL
75.0/100 × V₁ = 25.0/100 × 300
To isolate V₁, we will rearrange the formula:
V₁ = (25.0/100 × 300) / (75.0/100)
V₁ = (0.25 × 300) / (0.75)
V₁ = 75 mL
Therefore, you would need 75 mL of the 75.0% v/v EtOH stock solution to prepare a 25.0% v/v EtOH solution in a total volume of 300 mL.