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March 30, 2017

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Find the equation of the asymptotes for the hyperbola defined by the equation:

((y + 4)^2 / 36) - ((x - 3)^2 / 25) = 1

  • Algebra 2 - ,

    centre is (-4,3)
    and the asymptotes go through the centre
    slopes are -5/6

    y = (5/6)x + b
    at (-4,3)
    3 = (5/6)(-4) + b
    b = 39/5
    y = (5/6)x + 39/5

    or

    y = (-5/6)x + b
    3 = (-5/6)(-4) + b
    b = -1/3

    y = (-5/6)x - 1/3

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