Posted by **Tristan** on Saturday, May 11, 2013 at 10:47pm.

Find the equation of the asymptotes for the hyperbola defined by the equation:

((y + 4)^2 / 36) - ((x - 3)^2 / 25) = 1

- Algebra 2 -
**Reiny**, Sunday, May 12, 2013 at 12:41am
centre is (-4,3)

and the asymptotes go through the centre

slopes are -5/6

y = (5/6)x + b

at (-4,3)

3 = (5/6)(-4) + b

b = 39/5

y = (5/6)x + 39/5

or

y = (-5/6)x + b

3 = (-5/6)(-4) + b

b = -1/3

y = (-5/6)x - 1/3

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