Posted by Tristan on Saturday, May 11, 2013 at 10:47pm.
Find the equation of the asymptotes for the hyperbola defined by the equation:
((y + 4)^2 / 36)  ((x  3)^2 / 25) = 1

Algebra 2  Reiny, Sunday, May 12, 2013 at 12:41am
centre is (4,3)
and the asymptotes go through the centre
slopes are 5/6
y = (5/6)x + b
at (4,3)
3 = (5/6)(4) + b
b = 39/5
y = (5/6)x + 39/5
or
y = (5/6)x + b
3 = (5/6)(4) + b
b = 1/3
y = (5/6)x  1/3
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