Posted by **birju** on Friday, May 10, 2013 at 10:15pm.

Temperature of a diatomic gas is 300k. If the moment of inertia of its molecules is 8.28*10^-38 gm-cm^2. Calculate their root mean square angular velocity.

- Physics -
**birju - HELP PLEASE!!!!!!!**, Friday, May 10, 2013 at 11:23pm
Please give the complete solution

- Physics -
**Elena**, Saturday, May 11, 2013 at 3:54am
I=8.28•10⁻³⁸ g•cm²=8.28•10⁻⁴⁵kg•m²,

I=2mr²/3 =>

radius of diatomic molecule

r=sqrt{3•I/2m}

Root mean square speed v =sqrt{3kT/m}.

v = ωr.

Angular root mean square speed

ω=v/r= =sqrt{2kT/I} =

=sqrt{2•1.38•10⁻²³•300/8.28•10⁻⁴⁵}=

=1•10¹² rad/s

- Physics -
**birju - HELP PLEASE!!!!!!!**, Monday, May 13, 2013 at 9:14pm
Thanks, Elena...

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