Posted by birju on Friday, May 10, 2013 at 10:15pm.
Temperature of a diatomic gas is 300k. If the moment of inertia of its molecules is 8.28*10^38 gmcm^2. Calculate their root mean square angular velocity.

Physics  birju  HELP PLEASE!!!!!!!, Friday, May 10, 2013 at 11:23pm
Please give the complete solution

Physics  Elena, Saturday, May 11, 2013 at 3:54am
I=8.28•10⁻³⁸ g•cm²=8.28•10⁻⁴⁵kg•m²,
I=2mr²/3 =>
radius of diatomic molecule
r=sqrt{3•I/2m}
Root mean square speed v =sqrt{3kT/m}.
v = ωr.
Angular root mean square speed
ω=v/r= =sqrt{2kT/I} =
=sqrt{2•1.38•10⁻²³•300/8.28•10⁻⁴⁵}=
=1•10¹² rad/s

Physics  birju  HELP PLEASE!!!!!!!, Monday, May 13, 2013 at 9:14pm
Thanks, Elena...
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