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March 28, 2017

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Temperature of a diatomic gas is 300k. If the moment of inertia of its molecules is 8.28*10^-38 gm-cm^2. Calculate their root mean square angular velocity.

  • Physics - ,

    Please give the complete solution

  • Physics - ,

    I=8.28•10⁻³⁸ g•cm²=8.28•10⁻⁴⁵kg•m²,
    I=2mr²/3 =>
    radius of diatomic molecule
    r=sqrt{3•I/2m}
    Root mean square speed v =sqrt{3kT/m}.
    v = ωr.
    Angular root mean square speed
    ω=v/r= =sqrt{2kT/I} =
    =sqrt{2•1.38•10⁻²³•300/8.28•10⁻⁴⁵}=
    =1•10¹² rad/s

  • Physics - ,

    Thanks, Elena...

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