for an aqueous solution having Calcl2 (2molar) and Mgcl2 (5molal) and specified gravity of solution is 1.145 calculate molality of chloride ion and molality if chloride ion.
2 M CaCl2 = 2 mols CaCl2/L soln.
2 mol = 111 x 2 = 222 g (but that's an estimate--you recalculate it).
Use density to calculate mass of 1L soln. That will be 1145grams.
mass solvent = 1145g-222g = ?g and convert to kg. Then
mols Cl in CaCl2 = 4 (2*2)
mols Cl in MgCl2 = 10 (2*5)
Total mols Cl^- = 14
m Cl^- = mols Cl^-/kg solvent.
To calculate the molality of chloride ion in the given aqueous solution, we need to first convert the concentration from molarity to molality.
1. Determine the moles of chloride ions for each salt:
For CaCl2:
- Molarity = 2 mol/L
- Moles of chloride ions = 2 moles/L * 2 L = 4 moles
For MgCl2:
- Molality = 5 mol/kg
- Moles of chloride ions = 5 moles/kg * 1 kg = 5 moles
2. Determine the total moles of chloride ions in the solution by summing the moles of chloride ions from each salt:
Total moles of chloride ions = 4 moles + 5 moles = 9 moles
3. Calculate the mass of water in the solution:
The mass of water can be determined using the specific gravity and the density of water at a specified temperature. Unfortunately, the density of water is required to perform this calculation, which is not provided in the question.
Without the density of water, it is not possible to determine the mass of water and, subsequently, the molality of chloride ions.
Please provide the density of water or any additional information required to calculate the mass of water for further assistance.