Posted by **Claire ** on Thursday, May 9, 2013 at 7:06pm.

Find the area of the region between the curve y^2=4x and the line x=3.

- MATH Calculus Homework -
**bobpursley**, Thursday, May 9, 2013 at 7:20pm
ok, sketch it.

area=INT2ydx from x=0 to 3

area=INT 2*sqrt(4x) dx

= INT 2*2sqrtx dx from x=0 to x^3

= 4*2/3 x^3 over limits

= 8/3 *27

check my work

- MATH Calculus Homework -
**Claire **, Thursday, May 9, 2013 at 7:31pm
I sorry but I don't undestand. What would be f(x) and g(x)?

- MATH Calculus Homework -
**bobpursley**, Thursday, May 9, 2013 at 7:34pm
I have no idea what you mean by F(x) or g(x).

- MATH Calculus Homework -
**Prue **, Thursday, May 9, 2013 at 7:37pm
I'm sorry. For the equation that I have to use for this it is:

Integral symbol(f(x)-g(x))dx

- MATH Calculus Homework -
**Prue **, Thursday, May 9, 2013 at 7:42pm
Sorry I posted into the wrong conversation, please ignore me. Thank you.

- MATH Calculus Homework -
**bobpursley**, Thursday, May 9, 2013 at 7:48pm
f(x)=sqrt(4x) g(x)=-sqrt(4x)

f(x)-g(x)=2*f(x)

- MATH Calculus Homework -
**Claire**, Thursday, May 9, 2013 at 7:51pm
Why is g(x)=-sqrt(4x)?

- MATH Calculus Homework -
**bobpursley**, Thursday, May 9, 2013 at 8:15pm
sketch it!

sqrt4x=+- 2sqrtx

- MATH Calculus Homework -
**Claire**, Thursday, May 9, 2013 at 8:23pm
Oh I forgot about the ± sign. THANK YOU!!

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