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March 24, 2017

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Find the area of the region between the curve y^2=4x and the line x=3.

  • MATH Calculus Homework - ,

    ok, sketch it.

    area=INT2ydx from x=0 to 3

    area=INT 2*sqrt(4x) dx
    = INT 2*2sqrtx dx from x=0 to x^3

    = 4*2/3 x^3 over limits
    = 8/3 *27

    check my work

  • MATH Calculus Homework - ,

    I sorry but I don't undestand. What would be f(x) and g(x)?

  • MATH Calculus Homework - ,

    I have no idea what you mean by F(x) or g(x).

  • MATH Calculus Homework - ,

    I'm sorry. For the equation that I have to use for this it is:

    Integral symbol(f(x)-g(x))dx

  • MATH Calculus Homework - ,

    Sorry I posted into the wrong conversation, please ignore me. Thank you.

  • MATH Calculus Homework - ,

    f(x)=sqrt(4x) g(x)=-sqrt(4x)

    f(x)-g(x)=2*f(x)

  • MATH Calculus Homework - ,

    Why is g(x)=-sqrt(4x)?

  • MATH Calculus Homework - ,

    sketch it!

    sqrt4x=+- 2sqrtx

  • MATH Calculus Homework - ,

    Oh I forgot about the ± sign. THANK YOU!!

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