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March 30, 2017

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Solve the equation
log[1/6](x^2+x)-log[1/6](x^2-x)=-2

  • log[1/6](x^2+x)-log[1/6](x^2-x)=-2 - ,

    raise 1/6 to the power

    (x^2+x)/(x^2-x) = (1/6)^-2 = 36
    (x+1)/(x-1) = 36
    x = 37/35

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