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December 21, 2014

December 21, 2014

Posted by **Audrey** on Thursday, May 9, 2013 at 5:18pm.

log[1/6](x^2+x)-log[1/6](x^2-x)=-2

- log[1/6](x^2+x)-log[1/6](x^2-x)=-2 -
**Steve**, Thursday, May 9, 2013 at 5:35pmraise 1/6 to the power

(x^2+x)/(x^2-x) = (1/6)^-2 = 36

(x+1)/(x-1) = 36

x = 37/35

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