Post a New Question

Posted by Audrey on Thursday, May 9, 2013 at 5:18pm.

Solve the equation log[1/6](x^2+x)-log[1/6](x^2-x)=-2

raise 1/6 to the power (x^2+x)/(x^2-x) = (1/6)^-2 = 36 (x+1)/(x-1) = 36 x = 37/35

More Related Questions