MATH
posted by DANNY on .
the area of a certain rectangle is 288yd squared. the perimeter is 68yd. if you double the length and width,what will be the area and perimeter of the new rectangle?

L*W = 288
2L*2W = 4*L*W = 4*288 = 1152 yds^2.
2L+2W = 68
2(2L+2W) = 2*68 = 136 yds.