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March 5, 2015

March 5, 2015

Posted by **Zoe** on Thursday, May 9, 2013 at 10:40am.

90

135

180

225

270

315

405

450

495

and 540?

- math trig -
**Reiny**, Thursday, May 9, 2013 at 12:33pmI will do of these,

for 135° :

assume the axle is 20.5 above the ground

height above axle:

sin135 = h/20.5

h = 20.5sin135 = appr 14.5 m

so height above the ground = 20.5 + 14.5 = 35

for 315°

height from axle :

sin 315 = h/20.5

h = 20.5sin135 = appr - 14.5

notice the position would be BELOW the axle

so height above ground = 20.5 - 14.5 = 6 m

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