Two bike riders ride around a circular track, 1st rider completes one round in 12 minutes, the second rider completes a round in 16 minutes. If they start at the same time and fo in the same direction, how many turn before they meet at the same place again.

LCM(12,16) = 48

so, 48/12=4 and 48/16=3 laps, respectively.

thank you so very much, it is really appreciated

To find the number of times they meet at the same place again, we need to find the lowest common multiple (LCM) of their time taken to complete one round.

The 1st rider completes one round in 12 minutes, and the 2nd rider completes one round in 16 minutes.

To find the LCM, we can list the multiples of 12 and 16 until we find a common multiple.

Multiples of 12: 12, 24, 36, 48, 60, 72, 84, 96, ...

Multiples of 16: 16, 32, 48, 64, 80, 96, ...

The first common multiple is 48. Therefore, they will meet at the same place after completing 48 minutes.

To find the number of times they meet at the same place again, we can divide the total time taken to complete 48 minutes by the time taken by the 1st rider to complete one round.

48 / 12 = 4

Therefore, they will meet at the same place again after 4 rounds.