posted by Anonymous on .
A uniform 5.9 T magnetic ﬁeld points north.
If an electron moves vertically downward (toward the ground) with a speed of 0.85 × 107
m/s through this ﬁeld.
The charge on a proton is 1.60×10−19
a) What is the magnitude of the force acting
Answer in units of N
sinα = sin180= 0 => F=0