DVD player 17 inches wide, protected by 3/4 inch of foam, placed in a carton that is 1/8 of an inch, how wide is the carton?
17 + 1 1/2 + 1/4 = ?
Should it be 1/4 or 1/8, if 1/4 then ans is 18.75 and if 1/8 then it is 18 5/8
The carton is 1/8 inch on both sides so the total is 1/4 inch.
Ans is 18.75
Yep.
To find the width of the carton, we need to subtract the width of the DVD player and the foam from the total width.
Given:
- Width of the DVD player = 17 inches
- Thickness of the foam = 3/4 inch
- Thickness of the carton = 1/8 inch
First, let's find the combined width of the DVD player and the foam:
Width of DVD player + Thickness of foam = 17 inches + (3/4) inches
To add 17 inches and 3/4 inch, we need to have a common denominator. Since 4 is the least common multiple of 1 and 4, we can convert 17 inches to a fraction with the denominator 4:
17 inches = (17 * 4)/(1 * 4) = 68/4 inches
Now we can add the fractions:
68/4 inches + (3/4) inches = (68 + 3)/4 inches = 71/4 inches
The combined width of the DVD player and the foam is 71/4 inches.
Next, we need to subtract the thickness of the carton from the combined width:
Combined width - Thickness of carton = (71/4) inches - (1/8) inches
To subtract fractions, we need a common denominator, which in this case is 8:
(71/4) inches - (1/8) inches = (71/4) inches - (1/8) inches * (2/2) = (71/4) inches - (2/8) inches
Now we can subtract the fractions:
(71/4) inches - (2/8) inches = (71 - 2)/4 inches = 69/4 inches
Therefore, the width of the carton is 69/4 inches or 17.25 inches.