solve this equation. log (2x + 1) base 2 = -3
Since we're taking logs base 2, the equation means that
2x+1 = 2^(-3) = 1/8
2x = -7/8
x = -7/16
sure enough,
log_2(1/8) = -3
2x+1 = 2^(-3) = 1/8
2x = -7/8
x = -7/16
sure enough,
log_2(1/8) = -3