Maths
posted by HELP!! on .
The number 1000 can be written in several ways as a sum of one or more consecutive positive integers, for instance, 1000=1000 (one summand) or 1000=198+199+200+201+202 (five summands). Find the largest possible number of summands in a representation of 1000 as a sum of consecutive positive integers.

If there are k summands, starting at n, we want n as small as possible.
n+(n+1)+...+(n+k) = 1000
kn + k(k1)/2 = 1000
k^2 + (2n1)k  2000 = 0
so
4n^24n+8001 is a perfect square
If n=28, 4n^2+4n+8001=105^2 and k=25
check:
summing the arithmetic sequence starting at 28 for 25 terms,
S25 = 25/2 (28*2+24) = 25/2*80 = 1000
So, it looks like 25 is the maximum number of summands.