if the endpoint in the tritration of the KHC8H4O4 solution with the NaOH solution is mistakenly surpressed(too pink),will the molar concentration of the NaOH solution be reported too high or too low?explain
I answered this last night.
If the endpoint in the titration of the KHC8H4O4 solution with the NaOH solution is mistakenly suppressed (too pink), the molar concentration of the NaOH solution will be reported as too low.
During the titration process, a known volume of NaOH solution (with a known concentration) is added to the KHC8H4O4 solution (whose concentration is to be determined). The reaction between the two substances continues until an equivalence point is reached, indicated by a color change in the solution.
In this case, if the endpoint is mistakenly suppressed and appears too pink, it means that the color change (indicating the equivalence point) may not be clearly visible or may occur at a lower pH than expected. This means that the required amount of NaOH to reach the equivalence point would not have been fully added.
As a result, the volume of NaOH solution would be less than what it should have been to reach the equivalence point, resulting in a lower reported molar concentration of NaOH.