I assume you are implying that we don't need a fence along the house.
let the length be y m (the single side)
let the width be x m
so we know that 2x + y = 60
or y = 60 - 2x
Area = xy
= -2x^2 + 60x
At this point I don't if you know Calculus or not.
If you do, then
d(Area)/dx = -4x + 60
= 0 for a max of area
-4x + 60 = 0
x = 15
then y = 30
if you don't take Calculus, we have to complete the square
area = -2(x^2 - 30x)
= -2(x^2 - 30x + 225 - 225)
= -2((x-15)^2 - 225)
= -2(x-15)^2 + 450
so the area is a maximum when x = 15
and then y = 60-30 = 30
by either method,
the width has to be 15 m, and the length has to be 30 m for a maximum area of 15(30) or 450 m^2
math pre algebra - a kennel owner is buying a new building he want the space ...
Agility Training - Please check my answer thanks :) The organization that ...
Calc. - A dog kennel owner needs to build a dog run (rectangular area) adjacent ...
Math - A dog kennel owner needs to build a dog run (rectangular area) adjacent ...
calculus - A dog kennel with four pens is to be constructed. The pens will be ...
business law - Jean owns five acres of land in an area of single-family homes on...
Business Law - Jean owns five acres of land in an area of single-family homes on...
Math - If Steve has 120 feet of fence to make a rectangular kennel and he will ...
Basic college math - A rectangular kennel measures 26 1/2 feet by 20 1/4 feet. ...
Literature - "Slowly, silently, now the moon Walks the night in her silver shoon...