Posted by Ruth on .
2500 students take a college entrance exam. The scores on the exam have an approximate normal distribution with mean u = 52 points and a standard deviation o = 11 points. Estimate the percentage of students scoring 52 points or more.
How would you do this?
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Multiply by 100.