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February 1, 2015

February 1, 2015

Posted by **Need help fast** on Tuesday, May 7, 2013 at 11:13pm.

- Algebra -
**Anonymous**, Monday, March 3, 2014 at 1:10pmThis is quite confusing problem and the people setting the problem should keep common sense handy when designing a problem.

The confusion is created because Dwane and Patti live in the same house but leave at different times to go to meet the same person Martha at the same time and point on the road. More confusing is Martha also leaves her house same time as Dwane. Considering this is car driving (the distance is 74.4 miles) it doesn't make much sense and then all-three meet in-between. That it just not a close to real life situation.

In any case, the once this is understood the problem is simple: Speeds P(Patti)+D(Dwane)+M(Martha)=3x54, 1.1P=0.6D (As Patti and Dwane travel the same distance in 1.1 hr and 0.6 hr), and 0.6D+0.6M=74.4 (Dwane and Martha's distance added to the total distance).

Solving these three equations:

P+D+M=162

1.1P=0.6D

0.6D+0.6M=74.4

That gives:

P=38 mph

D=69 2/3 or 69.67 mph

and

M=54 1/3 or 54.33 mph

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