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December 20, 2014

December 20, 2014

Posted by **Steve** on Tuesday, May 7, 2013 at 10:31pm.

f(x)= log_5((x-4)^3) + e^((x-1)(x+1))

Log_5 means log base 5

- math -
**Steve**, Wednesday, May 8, 2013 at 2:44pmf(x)= log_5((x-4)^3) + e^((x-1)(x+1))

= 3log_5(x-4) + e^(x^2-1)

f' = 3/(ln5 (x-4)) + 2x e^(x^2-1)

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