find derivative of
f(x)= log_5((x-4)^3) + e^((x-1)(x+1))
Log_5 means log base 5
f(x)= log_5((x-4)^3) + e^((x-1)(x+1))
= 3log_5(x-4) + e^(x^2-1)
f' = 3/(ln5 (x-4)) + 2x e^(x^2-1)
f(x)= log_5((x-4)^3) + e^((x-1)(x+1))
Log_5 means log base 5
= 3log_5(x-4) + e^(x^2-1)
f' = 3/(ln5 (x-4)) + 2x e^(x^2-1)