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September 14, 2014

September 14, 2014

Posted by **Sabrina** on Tuesday, May 7, 2013 at 10:19pm.

- Algebra -
**Steve**, Tuesday, May 7, 2013 at 10:39pmit opens up, because the (x^2) is positive. if it was negative, it would open down. The vertex is as follows:

to find the value of vertex, solve first for when x=o, then when y=0

- Algebra -
**Different Steve**, Wednesday, May 8, 2013 at 11:10amActually, note that

y=-x^2+x-5

so it opens downward

y = -(x^2 - x + 1/4) - 5 + 1/4

= -(x - 1/2)^2 - 19/4

Now it should be clear where the vertex lies.

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