Posted by **Brian** on Tuesday, May 7, 2013 at 5:48am.

A piece of wire 40 m long is cut into two pieces. One piece is bent

into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a

maximum=

minimum=

Find the length of the wire used

- Calculus -
**Steve**, Tuesday, May 7, 2013 at 9:54am
If the sides are s and , respectively,

4s+3t = 40

a = √3/4t^2 + s^2

now express a as a function of s (or t) only, and find its extrema (where a'=0)

- Calculus -
**steve**, Monday, November 3, 2014 at 3:41pm
(sqrt(3)/4)t^2+((40-3t)/4)^2

- Calculus -
**Anonymous**, Thursday, May 26, 2016 at 6:20am
81

- Calculus -
**Brian**, Tuesday, January 17, 2017 at 9:10am

## Answer This Question

## Related Questions

- calculus - A five feet piece of wire is cut into two pieces. One Piece is bent ...
- Calculus - A piece of wire 40 m long is cut into two pieces. One piece is bent ...
- Calculus - A piece of wire 12 m long is cut into two pieces. One piece is bent ...
- Calculus - A wire 7 meters long is cut into two pieces. One piece is bent into ...
- Calculus - A wire 4 meters long is cut into two pieces. One piece is bent into a...
- math - A 2 feet piece of wire is cut into two pieces and once piece is bent into...
- calculus - A piece of wire 18 m long is cut into two pieces. One piece is bent ...
- calculus help please - A piece of wire 14 m long is cut into two pieces. One ...
- Calculus 1 - A piece of wire 23 m long is cut into two pieces. One piece is bent...
- Calculus Help Please Urgent!!! - A piece of wire 14 m long is cut into two ...

More Related Questions