Posted by Brian on Tuesday, May 7, 2013 at 5:48am.
A piece of wire 40 m long is cut into two pieces. One piece is bent
into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a
maximum=
minimum=
Find the length of the wire used

Calculus  Steve, Tuesday, May 7, 2013 at 9:54am
If the sides are s and , respectively,
4s+3t = 40
a = √3/4t^2 + s^2
now express a as a function of s (or t) only, and find its extrema (where a'=0)

Calculus  steve, Monday, November 3, 2014 at 3:41pm
(sqrt(3)/4)t^2+((403t)/4)^2

Calculus  Anonymous, Thursday, May 26, 2016 at 6:20am
81

Calculus  Brian, Tuesday, January 17, 2017 at 9:10am
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