Posted by **Brian** on Tuesday, May 7, 2013 at 5:48am.

A piece of wire 40 m long is cut into two pieces. One piece is bent

into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a

maximum=

minimum=

Find the length of the wire used

- Calculus -
**Steve**, Tuesday, May 7, 2013 at 9:54am
If the sides are s and , respectively,

4s+3t = 40

a = √3/4t^2 + s^2

now express a as a function of s (or t) only, and find its extrema (where a'=0)

- Calculus -
**steve**, Monday, November 3, 2014 at 3:41pm
(sqrt(3)/4)t^2+((40-3t)/4)^2

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