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March 28, 2017

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A piece of wire 40 m long is cut into two pieces. One piece is bent
into a square and the other is bent into an equilateral triangle. How should the wire be cut so that the total area enclosed is a
maximum=
minimum=
Find the length of the wire used

  • Calculus - ,

    If the sides are s and , respectively,

    4s+3t = 40
    a = √3/4t^2 + s^2

    now express a as a function of s (or t) only, and find its extrema (where a'=0)

  • Calculus - ,

    (sqrt(3)/4)t^2+((40-3t)/4)^2

  • Calculus - ,

    81

  • Calculus - ,

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