Tuesday

March 31, 2015

March 31, 2015

Posted by **diego** on Monday, May 6, 2013 at 11:49pm.

- calculus -
**Steve**, Tuesday, May 7, 2013 at 4:30amv = ∫[0,2]π(R^2-r^2) dx

where R=12 and r=y+4

v = π∫[0,2](144-(x^3+4)^2) dx

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