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January 31, 2015

January 31, 2015

Posted by **dylan** on Monday, May 6, 2013 at 9:59pm.

- parabolas -
**Reiny**, Monday, May 6, 2013 at 10:33pmThe distance between the vertex and the focus is 3

so the directrix must be x =2 (from -1 to 2 is 3)

let (x,y) be any point on our parabola

√( (x+4)^2 + y^2) = √( (x-2)^2 + 0)

square both sides and expand

x^2 + 8x + 16 + y^2 = x^2 - 4x + 4

y^2 = -12x - 12

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