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March 26, 2017

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While waiting to board a helicopter, you notice that the rotor's motion changed from 340 rev/min to 265 rev/min in one minute. Assuming that this acceleration remains constant, calculate how much longer (in seconds) it will take for the rotor to stop.

  • physics - ,

    a = dv/dt = (265-340)/60 = -1.25 rev/sec

    v = Vi + a t
    0 = 265 - 1.25 t
    t = 212 seconds

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