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Related Rates

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A particle moves along a path described by y=x^2. At what point along the curve are x and y changing at the same rate? Find this rate if at time t we have x=sin t and y= sin^2t.

I solved the first part and got (1/2, 1/4), but I have no idea how to tackle the second part. Help is much appreciated.

  • Related Rates - ,

    dy/dt = dy/dx * dx/dt
    but
    dy/dx = 2x
    so
    dy/dt = 2 x dx/dt
    so when 2 x = 1 (when the slope = 1 of course)

    x = 1/2 then y = 1/4

    x = sin t
    when is sin t = 1/2
    when t = 30 degrees or pi/6 radians
    dx/dt = cos t = cos 30 = (sqrt 3 )/ 2
    dy/dt = 2 sin t cos t = 2(1/2)(sqrt 3/2) sure enough

  • Related Rates - ,

    Thank you very much. I understand it now. :-)

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