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November 28, 2014

November 28, 2014

Posted by **Shane** on Monday, May 6, 2013 at 4:21pm.

- maths -
**Steve**, Monday, May 6, 2013 at 4:48pm(2x^3/3y^4)^2 * (x/3y)^-2

4x^6/9y^8 * 9y^2/x^2

4x^4/y^6

(a - 1/a) / (a^2-1)

((a^2-1)/a) / (a^2-1)

1/a

3^(a+2) 9^(2a+1) / 6^2 3^(5a+3)

3^(a+2) 3^(4a+2) / 2^2 3^2 3^(5a+3)

3^(5a+4) / 4*3^(5a+5)

1/12

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